![]() Last month, I posted 2 ReactJS interview questions ? - Advance Questions and Commonly Asked Question and got a significant welcome by dev.to community. 3 Modern Ways to Center an Element with CSS 4 JS Coding Question #1: Count all vowels 5 JS Coding Question #2: Reverse a string 6 JS Coding Question #3: Is Palindrome 7 JS Coding Question #4: Remove Duplicates 8 JS Coding Question #5: Find Min and Max 9 JS Coding Question #6: Is Anagram 10 JS Coding Question #7: Classic Fizz Buzz (one-liner ?) 11 JS Coding Question #8: Capitalize All Words In A Sentence ?? 12 JS Coding Question #9: Get Max Character In A String 13 JS Coding Question #10: Is Balanced Parenthesis 14 (Compilation) Front-End Most Commonly Asked Interview Questions 15 (Compilation) 10 Common Javascript Coding Interview Questions 16 React Interview Questions (Entry - Junior Level) 17 React Interview Questions (Mid - Senior Level) 18 10 ReactJS Coding Challenge (?Coding Interview Prep?) 19 JS Coding Question #11: Are Two Object Equal (?3 Solutions?) 20 ReactJS Tic-Tac-Toe (?Passed Job Interview?) 21 CSS Interview Question: Create Responsive Design (1 Column / 3 Column) 22 CSS Interview Question: Center HTML Element (3 Approaches?) 4 Even though it is divisible by 4, the year 2100 will not be a leap year because it will be a centenal, but not divisible by 400.1 JavaScript Interview Questions and Answers you should know - Junior and Senior 2 CSS and HTML Interview Questions and Answers. 4 Even though it is divisible by 4, the year 1900 was not a leap year because it was a centenal, but not divisible by 400.Ĭase No. 3 The year 2400 will be a leap year because it will be a centenal and divisible by 400.Ĭase No. 3 The year 2000 was a leap year because it was a centenal and divisible by 400.Ĭase No. 2 The year 2020 will be a leap year because it is divisible by 4 and will not be a centenal.Ĭase No. 2 The year 2016 was a leap year because it is divisible by 4 and was not a centenal.Ĭase No. 1 The year 2019 will not be leap year because it is not divisible by 4.Ĭase No. ![]() 1 The year 2018 is not leap year because it is not divisible by 4.Ĭase No. 1 The year 2017 was not leap year because it is not divisible by 4.Ĭase No. 4 Even though it is divisible by 4, the year \(year) \(isNotVerb) a leap year because it \(isVerb) a centenal, but not divisible by 400.")Ĭase No. ![]() 3 The year \(year) \(isVerb) a leap year because it \(isVerb) a centenal and divisible by 400.") 2 The year \(year) \(isVerb) a leap year because it is divisible by 4 and \(isNotVerb) a centenal.") 1 The year \(year) \(isNotVerb) leap year because it is not divisible by 4.") Let isNotVerb = thisYear >= year ? thisYear = year ? "is not" : "was not" : "will not be" Let isVerb = thisYear >= year ? thisYear = year ? "is" : "was" : "will be" Let thisYear = ponent(.year, from: today) 4 Even though it is divisible by 4, the year 1900 is not a leap year because it is a centenal, but not divisible by 400.įor fun, you could also compare with today's year: let today = Date() 3 The year 2000 is a leap year because it is divisible by 4, is centenal and divisible by 400.Ĭase No. 2 The year 2020 is a leap year because it is divisible by 4 and non centenal.Ĭase No. 1 The year 2018 is not leap year because it is not evenly divisible by 4.Ĭase No. 4 Even though it is divisible by 4, the year \(year) is not a leap year because it is a centenal, but not divisible by 400.")Ĭase No. 3 The year \(year) is a leap year because it is divisible by 4, is centenal divisible by 400.") 2 The year \(year) is a leap year because it is divisible by 4 and non centenal.") 1 The year \(year) is not leap year because it is not evenly divisible by 4.") ![]() However, the message you give to user are not very didactic. if divisible by 4 and not divisible by 100, or.The logic is OK, as rule for leap year is the following : Below is an incomplete function for deciding if a given year is a leap year: The number(_:, isDivisibleBy:) function has been built into this playground to make this exercise easier. These decisions can be made inside a function. To decide if a year is a leap year, there are several decisions that have to be made: Appreciate anyone give me the correct answer, thanks in advance. I solved the problem as per below image, but I have not used func number(year, isDivisibleBy: 4). ![]()
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